Question

Among the following sets of reactants which one produces anisole ?

• A. \(C_6H_5OH ; NaOH ; CH_3l\)
• B. \(C_6H_5OH\) ; neutral \(FeCl_3\)
• C. \(C_6H_5 – CH_3 ; CH_3COCl; AlCl_3\)
• D. \(CH_3CHO ; RMgX\)

Answer 1

The Correct Option is A

 The question asks which set of reactants can be used to produce anisole. Anisole is an ether commonly synthesized through the Williamson Ether Synthesis method.

Step-by-step Explanation

1. In the Williamson Ether Synthesis, ether is formed by the reaction of an alkoxide ion with an alkyl halide.
2. The reactants for this synthesis are typically a phenol, a base (such as NaOH), and an alkyl halide.
3. Analyzing the given options:
   • \(C_6H_5OH ; NaOH ; CH_3I\): This combination can produce anisole. Here, sodium phenoxide (\(C_6H_5ONa\)) is formed when phenol (\(C_6H_5OH\)) reacts with NaOH. It then reacts with methyl iodide (\(CH_3I\)) to produce anisole (\(C_6H_5OCH_3\)) and NaI (sodium iodide).
   • \(C_6H_5OH\) ; neutral \(FeCl_3\): This is a test for phenols and does not produce anisole.
   • \(C_6H_5–CH_3 ; CH_3COCl; AlCl_3\): This is a Friedel-Crafts acylation reaction, producing acetophenone, not anisole.
   • \(CH_3CHO ; RMgX\): This is a Grignard reaction setup for producing alcohols, not ethers like anisole.
4. Therefore, the reactants \(C_6H_5OH ; NaOH ; CH_3I\) are the correct choice for producing anisole.

Conclusion

Among the options provided, the set of reactants \(C_6H_5OH ; NaOH ; CH_3I\) is used to produce anisole via the Williamson Ether Synthesis method.

Chemical Reaction

The chemical reaction can be represented as:

\(C_6H_5OH + NaOH \rightarrow C_6H_5ONa + H_2O\)

\(C_6H_5ONa + CH_3I \rightarrow C_6H_5OCH_3 + NaI\)