All the diodes in the circuit given below are ideal. Which of the following plots is/are correct when \( V_I \) (in Volts) is swept from \( -M \) to \( M \)?





In the given circuit with ideal diodes, the current-voltage relationship will change depending on the input voltage (\(V_I\)). The behavior of the circuit can be broken down into the following steps:
Step 1: Diode behavior when \(V_I\) is negative
When \(V_I\) is negative, the diodes will be reverse biased and no current will flow through the circuit. Therefore, the output voltage \(V_o\) will be 0 for negative \(V_I\), and the plot will be flat from \(-M\) to 0.
Step 2: Diode behavior when \(V_I\) is positive
When \(V_I\) is positive, the diodes will conduct and the output voltage will increase linearly with \(V_I\). This results in a linear relationship between \(V_o\) and \(V_I\) for positive \(V_I\). The correct plot is (A) for the output voltage and (D) for the current \(I_I\) in the circuit, where the current increases as \(V_I\) increases.

The diode in the circuit shown below is ideal. The input voltage (in Volts) is given by \[ V_I = 10 \sin(100\pi t), \quad {where time} \, t \, {is in seconds.} \] The time duration (in ms, rounded off to two decimal places) for which the diode is forward biased during one period of the input is (answer in ms). 