Acidified potassium dichromate (K\(_2\)Cr\(_2\)O\(_7\)), a potent oxidizing agent, converts sulphides (S\(^{2-}\)) into sulphur dioxide (SO\(_2\)).
The corresponding oxidation reaction is represented as:\[\text{S}^{2-} + 2H^+ + \text{Cr}_2\text{O}_7^{2-} → \text{SO}_2 + 2H_2O + 2Cr^{3+}\]Therefore, SO\(_2\) is the confirmed oxidation product of sulphides (S\(^{2-}\)) when treated with acidified potassium dichromate.
Final Answer: \[\boxed{\text{The correct product is SO}_(2)}\]