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According to the Taylor's tool life equation, if the cutting speed is halved with index \( n = 0.25 \), then the tool life:

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A useful shortcut derived from Taylor's equation is: \[ \frac{T_2}{T_1} = \left(\frac{V_1}{V_2}\right)^{\frac{1}{n}} \] Substituting the values gives: \((2)^{\frac{1}{0.25}} = 2^4 = 16\).

Updated On: Jul 9, 2026

Increases by 8 times
Decreases by 8 times
Decreases by 16 times
Increases by 16 times

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The Correct Option is D

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According to the Taylor's tool life equation, if the cutting speed is halved with index \( n = 0.25 \), then the tool life:

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The Correct Option is D

Solution and Explanation

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