Step 1: Use dimensions.
$[P] = ML^{-1}T^{-2}$ and $[V] = L^3$, so $[PV] = ML^2T^{-2}$.
Step 2: Match.
$ML^2T^{-2}$ is the dimension of energy. Momentum is $MLT^{-1}$, force is $MLT^{-2}$, impulse is $MLT^{-1}$.
Final Answer:
Option (B).
\[ \boxed{\text{Energy}} \]