Absolute minimum value of \( f(x) = (x - 2)^2 + 5 \) in the interval \( [-3, 2] \) is :
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Since a squared expression \( (x - 2)^2 \) is always non-negative (\( \ge 0 \)), its minimum possible value is \( 0 \), which occurs at \( x = 2 \). Thus, the absolute minimum value is simply \( 0 + 5 = 5 \).