Question:medium
ABCD is a quadrilateral with \(A(3,5)\), \(B(5,9)\) and \(C(3,7)\). If the line \(y=3x\) meets the sides \(AB\) and \(BC\) in points \(P\) and \(Q\) respectively, then \(PQ^2=\)
ABCD is a quadrilateral with \(A(3,5)\), \(B(5,9)\) and \(C(3,7)\). If the line \(y=3x\) meets the sides \(AB\) and \(BC\) in points \(P\) and \(Q\) respectively, then \(PQ^2=\)
Show Hint
To find the intersection of two lines:
• Find the equation of each line.
• Solve them simultaneously.
• Use the distance formula: \[ PQ^2=(x_2-x_1)^2+(y_2-y_1)^2. \]
• Find the equation of each line.
• Solve them simultaneously.
• Use the distance formula: \[ PQ^2=(x_2-x_1)^2+(y_2-y_1)^2. \]
Updated On: Jul 15, 2026
- \(121\)
- \(90\)
- \(169\)
- \(150\)
Show Solution
The Correct Option is B
Solution and Explanation
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