Question:hard

A young lady presents with fever, dysuria and pain in the lower abdomen. Uncomplicated acute cystitis was diagnosed. Which among the following is not true?

Show Hint

Significant bacteriuria needs high counts, not fewer than 10^3/ml.
Updated On: Jun 24, 2026
  • Nitrate test positive for the urine sample
  • E. coli colony count < 10^3 bacteria/ml
  • 1 pus cell per 7 fields in wet film of patient's urine
  • 1 bacillus per oil-immersion field in Gram-stained urine sample
Show Solution

The Correct Option is B

Solution and Explanation

Confirming a urinary tract infection rests on showing significant bacteriuria together with an inflammatory response. In acute uncomplicated cystitis caused by E. coli, several laboratory findings are expected. First, E. coli reduces nitrate to nitrite, so a positive nitrite dipstick is anticipated, validating option A. Second, the host responds with pyuria; finding pus cells in the wet film, as in option C, fits the picture of infection. Third, a quick screening method is to Gram-stain an uncentrifuged drop of urine, where seeing at least one organism per oil-immersion field predicts a colony count near 10^5 per ml, supporting option D. The discordant statement is the colony count of fewer than 10^3 per ml. By Kass criteria, counts at or above 10^5 per ml indicate true infection, and symptomatic women may be diagnosed at 10^2 to 10^3, but a count below 10^3 is conventionally read as insignificant or contamination and argues against, rather than for, cystitis. That statement is therefore the untrue one.
\[\boxed{\text{E. coli colony count } < 10^3 \text{ bacteria/ml}}\]
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