Question:medium

A turbine pump is designed to generate water head of 60 m. The impeller speed of the pump is 2000 rpm and the manometric efficiency is 70%. Neglecting the impeller blade curvature, the impeller diameter of the pump, in cm, is . (rounded off to two decimal places)

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Neglecting blade curvature means the exit whirl velocity equals the impeller tip speed, so the ideal head is u2 squared over g; link that to the manometric efficiency and the diameter formula.
Updated On: Aug 17, 2026
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Correct Answer: 27.69

Solution and Explanation

Step 1: Understanding the Concept:
A centrifugal (turbine) pump spins water outward and this spinning motion, not friction, is what raises the water's pressure head. Ignoring blade curvature means we treat the whole tip speed of the impeller as doing useful work on the water, which is the simplest form of Euler's pump theory.

Step 2: Key Formula or Approach:
Under this assumption the manometric head links directly to the tip speed as $H_m = \eta_{man}\, u_2^2 / g$. Once $u_2$ is found, convert it to a diameter through the angular speed of rotation, $\omega = 2\pi N/60$, using $u_2 = \omega r$ where $r$ is the impeller radius.

Step 3: Detailed Explanation:
Rearranging the head formula for tip speed: $u_2 = \sqrt{H_m g / \eta_{man}} = \sqrt{(60)(9.81)/0.70} = \sqrt{840.86} = 29.00\ m/s$.
The angular speed at 2000 rpm is $\omega = 2\pi (2000)/60 = 209.44\ rad/s$.
The impeller radius is then $r = u_2/\omega = 29.00/209.44 = 0.1385\ m$.
Doubling for the diameter, $D = 2r = 0.2769\ m$, which is $27.69\ cm$.

Step 4: Final Answer:
Working through the angular speed and radius gives the same impeller diameter, about 27.69 cm.
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