Question

A trickling filter receives an organic load of \(300~\mathrm{kg\ BOD/day}\) and has a filter volume of \(150~\mathrm{m^3}\). What is the organic loading rate of the filter?

• A. \(0.5~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
• B. \(2~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
• C. \(5~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
• D. \(10~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)

Hint:

Organic loading rate: \[ \boxed{ \text{Organic Loading} = \frac{\text{BOD Load (kg/day)}}{\text{Filter Volume (m}^3\text{)}} } \]

Answer 1

The Correct Option is B

Step 1: Recall the organic loading rate formula.
Organic loading rate for a trickling filter is found using $\text{Loading} = \dfrac{\text{Organic Load}}{\text{Filter Volume}}$.
Step 2: Substitute the given data.
Here the load is 300 kg BOD/day and the volume is $150\ m^3$, so loading $= \dfrac{300}{150} = 2$.
Step 3: Attach the units.
This works out to 2 kg BOD per cubic metre per day, matching one of the given options directly.
\[ \boxed{2\ \mathrm{kg\ BOD/m^3 \cdot day}} \]