Step 1: Note what conveyance actually means.
Conveyance $K$ is the part of Manning's formula that depends only on the channel section and roughness, defined so that $Q = K\sqrt{S}$.
Step 2: See that $K$ can be pulled straight out of the given $Q$ and $S$.
Since $Q$ and $S$ are both already given (5 m3/s and 1%), there is no need to compute area or hydraulic radius separately.
$K = Q / S^{0.5}$
Step 3: Plug in the numbers.
$S = 0.01$, so $S^{0.5} = 0.1$.
$K = 5 / 0.1 = 50\ \text{m}^3\text{s}^{-1}$
Step 4: Sanity check with units.
$K$ carries the same units as $Q$ because $S$ is dimensionless, which matches the 50 m3/s result.
Final Answer:
The bottom width, side slope, and n values are extra information here; the conveyance is 50 m3/s.
\[ \boxed{K = 50\ \text{m}^3\text{s}^{-1}} \]