Question:easy

A train is moving towards a stationary observer with speed \(34\) m/s. A train sounds a whistle of frequency \(450\) Hz. If the speed of sound is \(340\) m/s, the frequency heard by the observer in Hz is

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Source moving toward a stationary observer: f = f0 v/(v - vs).
Updated On: Oct 1, 2026
  • \(440\)
  • \(480\)
  • \(500\)
  • \(540\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Use wavelength compression:
In one period $\frac1{450}$ s, the train advances $\frac{34}{450}$ m, shortening the wavelength: $\lambda' = \frac{340}{450} - \frac{34}{450} = \frac{306}{450}$ m.

Step 2: Observed frequency:
$f' = \frac{v}{\lambda'} = \frac{340\times450}{306} = 500$ Hz.

Step 3: Sign check:
The frequency is higher than 450 Hz, as expected for an approaching source.

Final Answer:
The observer hears 500 Hz, option (C). \[ \boxed{500\text{ Hz}} \]
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