A thin rod of length 'L' is bent in the form of a circle. Its mass is 'M'. What force will act on mass 'm' placed at the centre of this circle? (G = constant of gravitation)
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Logic Tip: The gravitational field at the exact center of ANY uniform spherically or circularly symmetric mass distribution (like a ring, spherical shell, or solid sphere) is always zero due to perfect spatial cancellation. No calculation is needed if you recognize the symmetry!