Question:medium

A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is :

Updated On: Jan 13, 2026
  • 12 cm
  • 13 cm
  • 8.5 cm
  • \(\sqrt {119}\) cm
Show Solution

The Correct Option is D

Solution and Explanation

Given \(PQ^2 =144 - 25\), we know that the line from the center of the circle to the tangent is perpendicular to the tangent. Therefore, \(OP \perp PQ\). Applying the Pythagorean theorem in \(\text {ΔOPQ}\), we have:
applying Pythagoras theorem in triangle OPQ
\(OP^2 + PQ^2 = OQ^2\)
\(5^2 + PQ^2 =12^2\)
\(25 + PQ^2 =144\)
\(PQ^2 =144 - 25\)
\(PQ^2 =119\)
\(PQ = \sqrt {119} \text{ cm}\)

The correct option is (D): \(\sqrt {119} \text{ cm}\)

Was this answer helpful?
0