Given \(PQ^2 =144 - 25\), we know that the line from the center of the circle to the tangent is perpendicular to the tangent. Therefore, \(OP \perp PQ\). Applying the Pythagorean theorem in \(\text {ΔOPQ}\), we have:
\(OP^2 + PQ^2 = OQ^2\)
\(5^2 + PQ^2 =12^2\)
\(25 + PQ^2 =144\)
\(PQ^2 =144 - 25\)
\(PQ^2 =119\)
\(PQ = \sqrt {119} \text{ cm}\)
The correct option is (D): \(\sqrt {119} \text{ cm}\)
