Step 1: Boltzmann ratio.
\[ \frac{N_2}{N_1} = e^{-\Delta E / kT} \] with 10 particles up and 100 down, so the ratio is 0.1.
Step 2: Rearrange for temperature.
\[ T = \frac{\Delta E}{k \ln 10} \]
Step 3: Put in values.
With $\Delta E = 1.6\times10^{-20}$ J, this gives about 503.86 K.
Step 4: Answer.
\[ \boxed{503.86 \text{ K}} \]