Question:easy

A syringe has a volume of \(10.0 \text{cm}^3\) at a pressure of \(1\) atm. If the end is sealed and the plunger is pushed down (constant temperature), what will be the final volume when the pressure becomes \(3.5\) atm?

Show Hint

Use Boyle's law, P1V1 = P2V2, because temperature is constant.
Updated On: Oct 1, 2026
  • \(35.0 \text{cm}^3\)
  • \(2.86 \text{cm}^3\)
  • \(0.286 \text{cm}^3\)
  • \(3.50 \text{cm}^3\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Use the inverse relation:
At constant temperature, the volume of a fixed amount of gas is inversely proportional to its pressure. The pressure rises by a factor of 3.5, so the volume must fall by the same factor.

Step 2: Divide:
$V_2 = \dfrac{10.0}{3.5}$ cm$^3$. Since $3.5 \times 2.86 = 10.01$, we get $V_2 \approx 2.86$ cm$^3$.

Step 3: Sanity check:
The new volume must be smaller than 10.0 cm$^3$. Only 2.86 and 0.286 are smaller, and 0.286 cm$^3$ would need a pressure of 35 atm, so B is right.

Final Answer:
Dividing 10.0 cm3 by 3.5 gives a final volume of 2.86 cm3. \[ \boxed{\text{(B) }2.86\ \text{cm}^3} \]
Was this answer helpful?
0