Question:medium

A straight line passes through the point whose position vector is $\hat{k}$. The straight line also passes through the point of intersection of the lines $\vec{r} = \hat{j} + \lambda \hat{i}, \lambda \in \mathbb{R}$ and $\vec{r} = \hat{i} + s\hat{j}, s \in \mathbb{R}$. Then the equation of the straight line is:

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Direction vector of line through two points is their difference.
Updated On: Apr 24, 2026
  • $\vec{r} = \hat{k} + t(\hat{i} + \hat{j} - \hat{k}), \; t \in \mathbb{R}$
  • $\vec{r} = \hat{k} + t(\hat{i} - \hat{j} - \hat{k}), \; t \in \mathbb{R}$
  • $\vec{r} = \hat{k} + t(\hat{i} - \hat{j} + \hat{k}), \; t \in \mathbb{R}$
  • $\vec{r} = \hat{k} + t(-\hat{i} + \hat{j} + 2\hat{k}), \; t \in \mathbb{R}$
  • $\vec{r} = \hat{k} + t(-\hat{i} + 2\hat{j} - \hat{k}), \; t \in \mathbb{R}$
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The Correct Option is A

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