Question:medium

A stone projected with velocity u at an angle θ with the horizontal reaches maximum height H₁. When it is projected with velocity u at an angle ((π)/(2)-θ), it reaches maximum height H₂. The relation between the horizontal range R of the projectile, heights H₁ and H₂ is:

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Complementary angles give same range but different maximum heights.
Updated On: Mar 20, 2026
  • \(R=4\sqrt{H_1H_2}\)
  • \(R=4(H_1-H_2)\)
  • \(R=4(H_1+H_2)\)
  • R=(H₁²)/(H₂)
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The Correct Option is A

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