Assuming no power loss, the power in the primary coil equals the power in the secondary coil. The formula for power (P) is VI. Primary voltage ($V_p$) is 220 V. Secondary voltage ($V_s$) is 11000 V. Power (P) is 88 W. Calculate the secondary current ($I_s$).
88 = 11000
$\implies i = \frac{88}{11 \times 10^3} = 8 \times 10^{-3} \text{ A}$
$\implies i = 8 \text{ mA}$