Question:medium

A spring with force constant \(k\) is initially stretched by \(x_1\). If it is further stretched by \(x_2\), then the increase in its potential energy is

Show Hint

Always calculate change in spring energy using \(U_f - U_i\), not directly using final formula.
Updated On: May 8, 2026
  • \(\frac{1}{2}k(x_2 - x_1)^2\)
  • \(\frac{1}{2}k x_2 (x_2 + 2x_1)\)
  • \(\frac{1}{2}k x_1^2 - \frac{1}{2}k x_2^2\)
  • \(\frac{1}{2}k (x_1 + x_2)^2\)
  • \(\frac{1}{2}k (x_1^2 + x_2^2)\)
Show Solution

The Correct Option is B

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