Question:medium

A sound wave travels from a region of air at \(20^{\circ }\text{C}\) into a region at \(40^{\circ }\text{C}\). What is the ratio of the wavelengths (\(\lambda _{40}/\lambda _{20}\)), if the frequency remains constant?

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The speed of sound in a gas is proportional to the square root of absolute temperature, and the frequency stays constant.
Updated On: Nov 12, 2026
  • \(\sqrt{\frac{313}{293}}\)
  • \(\frac{313}{293}\)
  • \(\sqrt{\frac{40}{20}}\)
  • \(\frac{40}{20}\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Speed ratio
$\frac{v_{40}}{v_{20}}=\sqrt{\frac{T_{40}}{T_{20}}}=\sqrt{\frac{313}{293}}$.

Step 2: Frequency fixed
$\lambda=\frac{v}{f}$, so the wavelength ratio equals the speed ratio.

Step 3: Why the other options fail
Using $\frac{40}{20}$ or $\sqrt{\frac{40}{20}}$ uses Celsius values, but the law needs absolute temperature. The option $\frac{313}{293}$ forgets the square root.

Final Answer:
The ratio is the square root of 313/293. \[ \boxed{\text{(A) }\sqrt{\dfrac{313}{293}}} \]
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