Question:medium

A solid sphere is melted and recast into a right circular cone with a base radius equal to the radius of the sphere. What is the ratio of the height to the radius of the cone so formed?

Show Hint

Equal volumes with the same radius give h = 4r, a 4:1 ratio, which isn't among the first three choices.
Updated On: Jul 15, 2026
  • 4 : 3
  • 2 : 3
  • 3 : 4
  • None of these
Show Solution

The Correct Option is D

Solution and Explanation

Since the sphere's volume formula and the cone's volume formula share a common $\pi r^2$ (or $\pi r^3$) factor, most of the algebra cancels away quickly.

  1. Sphere volume: $\frac{4}{3}\pi r^3$.
  2. Cone volume with the same radius $r$: $\frac{1}{3}\pi r^2 h$.
  3. Setting them equal: $\frac{4}{3}\pi r^3 = \frac{1}{3}\pi r^2 h$.
  4. Dividing both sides by $\frac{1}{3}\pi r^2$: $4r = h$.

This gives a height-to-radius ratio of exactly $4:1$, which does not appear among the first three options.

So the correct answer is option D, none of these.

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