Question:medium

A solid mixture weighing $5 \text{ g}$ contains equal number of moles of $\text{Na}_2\text{CO}_3$ and $\text{NaHCO}_3$. This solid mixture was dissolved in $1 \text{ L}$ of water. What is the volume (in $\text{mL}$) of $0.1 \text{ M } \text{HCl}$ required to completely react with this $1 \text{ L}$ mixture solution?

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For acid-base titrations, the key step is to balance the reaction equations to find the correct stoichiometric ratio (moles of acid per mole of base). The volume of titrant is found using the formula $V_{\text{acid}} = n_{\text{acid}} / M_{\text{acid}}$.

Updated On: Mar 30, 2026

157.8
789.0
1578.0
946.8

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The Correct Option is B

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