Question:medium
A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. [Use \(\pi = 3.14\)]
A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. [Use \(\pi = 3.14\)]
Updated On: Jan 13, 2026
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Solution and Explanation
The pole is composed of two cylinders:
Larger cylinder height (h1) = 220 cm
Larger cylinder radius (r1) = \( \frac{24}{2} \) = 12 cm
Smaller cylinder height (h2) = 60 cm
Smaller cylinder radius (r2) = 8 cm
Total volume of the pole = Volume of larger cylinder + Volume of smaller cylinder
\(=\pi r_1^2h_1+\pi r_2^2h_2\)
\(=\pi (12)^2\times220+\pi (8)^2\times60\)
\(=\pi [144\times220+64\times60]\)
\(=35520\times3.14\)
\(= 1,11,532.8\text{ cm}^3\)
Mass of 1 cm3 iron = 8g
Mass of 111532.8 cm3 = \(111532.8 \times 8\) g = 892262.4 g = 892.262 Kg
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