Question:medium

A soap bubble of radius R is blown. After heating the solution, a second bubble of radius 2R is blown. The work required to blow the second bubble in comparison to that required for the first bubble is

Show Hint

Work is 8 pi r^2 T. Heating reduces T.
Updated On: Oct 1, 2026
  • slightly less than \(4\) times
  • exactly double
  • slightly less than double
  • slightly more than \(4\) times
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Formula:
$W=8\pi r^2T$.

Step 2: Ratio:
$\dfrac{W_2}{W_1}=\dfrac{(2R)^2T_2}{R^2T_1}=4\dfrac{T_2}{T_1}$.

Step 3: Temperature effect:
$T$ decreases with temperature, so $T_2<T_1$. The ratio is slightly below 4. Option (A).

Final Answer:
The ratio is 4 times T2/T1, and T2 is less than T1. \[ \boxed{A} \]
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