Question

A simple pendulum has a length of $ L = 2 \, \text{m} $. What is the time period of the pendulum? (Assume $ g = 9.8 \, \text{m/s}^2 $)

• A. \( 2 \, \text{s} \)
• B. \( 1 \, \text{s} \)
• C. \( 3 \, \text{s} \)
• D. \( 4 \, \text{s} \)

Hint:

Remember: The time period of a simple pendulum depends on the length and gravitational acceleration.

Answer 1

The Correct Option is A

Step 1: Apply the formula for the period of a simple pendulum
\[T = 2\pi \sqrt{\frac{L}{g}}\]Parameters: - Length \( L = 2 \, \text{m} \) - Gravitational acceleration \( g = 9.8 \, \text{m/s}^2 \)Calculation: \[T = 2\pi \sqrt{\frac{2}{9.8}} \approx 2 \, \text{s}\]
Answer:
The time period of the pendulum is \( 2 \, \text{s} \). The correct option is (1).