Step 1: Combined focal length:
$f = \frac{100}{16} = 6.25$ cm.
Step 2: Magnification and size:
With the image at $25$ cm, $m = 1 + \frac{25}{6.25} = 5$, so the image height is $5 \times 0.3 = 1.5$ cm.
Final Answer:
The image size is $1.5$ cm, option (B).
\[ \boxed{1.5\ \text{cm}} \]