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A silicon diode has a forward voltage drop of \(0.7\ \mathrm{V}\). If it is connected in series with a \(1\,\mathrm{k}\Omega\) resistor to a \(5\ \mathrm{V}\) supply, then the forward current is

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For a silicon diode, \[ \boxed{ V_D\approx0.7\ \mathrm{V} } \] and \[ \boxed{ I=\frac{V_{\text{supply}}-V_D}{R}. } \]

Updated On: Jul 14, 2026

\(3.3\ \mathrm{mA}\)
\(5.7\ \mathrm{mA}\)
\(5.0\ \mathrm{mA}\)
\(4.3\ \mathrm{mA}\)

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The Correct Option is D

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