Question

A sedimentation tank has a volume of \(1500~\mathrm{m^3}\) and a flow of \(3000~\mathrm{m^3/day}\). Detention time is

• A. 6 hours
• B. 12 hours
• C. 18 hours
• D. 24 hours

Hint:

Detention time: \[ \boxed{ t=\frac{V}{Q} } \] where \(V\) = tank volume and \(Q\) = flow rate.

Answer 1

The Correct Option is B

Step 1: Recall the detention time formula.
Detention time tells us how long water stays inside a tank on average, and it is found using $t = \dfrac{\text{Volume}}{\text{Flow rate}}$.
Step 2: Plug in the numbers.
Here, volume is $1500\ m^3$ and flow is $3000\ m^3/\text{day}$, so $t = \dfrac{1500}{3000} = 0.5$ day.
Step 3: Convert to hours.
Since one day has 24 hours, $0.5 \times 24 = 12$ hours.
\[ \boxed{12\ \text{hours}} \]