Question

A satellite is revolving round the earth with orbital speed ' \(V_0\) '. If it stops suddenly, the speed with which it will strike the surface of the earth would be ( \(V_e\) = escape velocity of a particle on earth's surface)

• A. \(\frac{V_e^2}{V_0}\)
• B. \(2 V_0\)
• C. \(\sqrt{V_e^2 - V_0^2}\)
• D. \(\sqrt{V_e^2 - 2 V_0^2}\)

Hint:

Relation: $V_e = \sqrt{2}\, V_0$

Answer 1

The Correct Option is C