Question:medium

A satellite is orbiting the Earth and dissipates energy due to some resistive forces. Its initial total mechanical energy is \(E\) (negative). If the radius of its orbit becomes half of the original value, what is the new total mechanical energy of the satellite?

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In satellite dynamics, total energy is always half of the potential energy (\(E = \frac{U}{2}\)) and equal to the negative of the kinetic energy (\(E = -K\)). If the radius decreases, the satellite actually speeds up (K increases) even though its total energy decreases!
Updated On: Apr 16, 2026
  • \(E/2\)
  • \(E/4\)
  • \(2E\)
  • \(4E\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
For a satellite orbiting the Earth in a circular orbit, the total mechanical energy $E$ is the sum of its kinetic and potential energies. Since the gravitational force provides the necessary centripetal force, the total mechanical energy depends solely on the radius of the orbit.
Step 2: Key Formula or Approach:
The total mechanical energy $E$ of a satellite of mass $m$ orbiting a planet of mass $M$ at a radius $r$ is given by the formula: \[ E = -\frac{GMm}{2r} \] where $G$ is the universal gravitational constant.
Step 3: Detailed Explanation:
Let the initial radius be $r$. The initial total mechanical energy is: \[ E = -\frac{GMm}{2r} \] When the satellite dissipates energy due to resistive forces, its orbital radius decreases. The new radius is given as $r' = \frac{r}{2}$.
The new total mechanical energy $E'$ becomes: \[ E' = -\frac{GMm}{2r'} = -\frac{GMm}{2 \left( \frac{r}{2} \right)} \] \[ E' = -\frac{2GMm}{2r} = 2 \left( -\frac{GMm}{2r} \right) \] Substituting the initial energy $E$: \[ E' = 2E \] Since $E$ is negative, $2E$ represents a more negative value, signifying a decrease in the total energy (energy dissipated).
Step 4: Final Answer:
The new total mechanical energy of the satellite is $2E$.
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