Question:medium

A satellite is in a circular orbit around Earth at an altitude where the orbital radius is exactly \(4\) times the radius of another satellite's orbit. If the first satellite has a time period of \(2\) hours, what is the time period of the second satellite (in hours)?

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Kepler's Third Law: \[ \boxed{ T^2\propto r^3 } \] or equivalently, \[ \boxed{ \frac{T_2}{T_1} = \left(\frac{r_2}{r_1}\right)^{3/2}. } \] Always determine carefully which orbit has the larger radius before substituting.
Updated On: Jul 14, 2026
  • \(8\)
  • \(16\)
  • \(64\)
  • \(24\)
Show Solution

The Correct Option is B

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