Question:medium
A resistor of resistance R, capacitor of capacitance C and inductor of inductance L are connected in parallel to an AC power source of voltage \( \varepsilon_0 \sin \omega t \). The maximum current through the resistance is half of the maximum current through the power source. Then value of R is:
Answer:
\( R = \sqrt{3}\left| \dfrac{1}{\omega C} - \omega L \right| \)
A resistor of resistance R, capacitor of capacitance C and inductor of inductance L are connected in parallel to an AC power source of voltage \( \varepsilon_0 \sin \omega t \). The maximum current through the resistance is half of the maximum current through the power source. Then value of R is:
Answer:
\( R = \sqrt{3}\left| \dfrac{1}{\omega C} - \omega L \right| \)
Show Hint
In parallel AC circuits, currents add vectorially, not algebraically.
Updated On: Mar 23, 2026
- \(\sqrt{3}\left|\frac{1}{\omega C}-\omega L\right|\)
- \(\sqrt{3}\left|\frac{1}{\omega C}+\omega L\right|\)
- \(\sqrt{5}\left|\frac{1}{\omega C}-\omega L\right|\)
- None of these
Show Solution
The Correct Option is A
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