Question:medium

A resistor of \( 400\,\Omega \) and an inductance of \( 0.4\,\text{H} \) are in series with an a.c. source of e.m.f. \( E = 200\sqrt{2}\sin(1000t) \). The power factor of the circuit is

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If $R = X_L$, then: \[ \cos\phi = \frac{1}{\sqrt{2}} \]
Updated On: May 4, 2026
  • $0.4$
  • $0.5$
  • \( \frac{1}{\sqrt{2}} \)
  • \( \frac{1}{\sqrt{3}} \)
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The Correct Option is C

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