Question

A resistor has three colour bands: Orange, Red and Black from left to right respectively. The value of resistance is

• A. \(16\,\Omega\)
• B. \(32\,\Omega\)
• C. \(320\,\Omega\)
• D. \(160\,\Omega\) \bigskip

Hint:

Remember the resistor colour code: \[ \text{Black}=0,\; \text{Brown}=1,\; \text{Red}=2,\; \text{Orange}=3,\; \text{Yellow}=4, \] \[ \text{Green}=5,\; \text{Blue}=6,\; \text{Violet}=7,\; \text{Grey}=8,\; \text{White}=9. \] For a three-band resistor, \[ \text{Resistance} = (\text{first two digits})\times10^{(\text{third band value})}. \]

Answer 1

The Correct Option is B

Concept: Resistor colour code: 1st band = first digit, 2nd band = second digit, 3rd band = multiplier (power of 10).

Step 1: Orange = 3, Red = 2, Black = 10⁰ = 1. Resistance = \(32 \times 1 = 32\,\Omega\).

Step 2: Write the final answer. \(\boxed{R=32\,\Omega}\)