A researcher performs an experiment on photoelectric effect using two metals A and B with unknown work functions. She illuminates the surfaces of A and B with monochromatic radiation of various frequencies and records the corresponding stopping potentials \((V_s)\). The graph shows the variation of stopping potential \((V_s)\) with the frequency of incident radiation \((\nu)\) for metals A and B.
Answer the following questions:
Question: 1
From the graph, the work functions of A and B are \((h\) is Planck's constant and \(e\) is the electronic charge\().\)
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Threshold frequency and work function are related by
\[
\phi=h\nu_0.
\]
The intercept on the frequency axis directly gives the threshold frequency.
the threshold frequencies for both A and B will decrease.
the slope of the parallel lines will not change but more electrons will be emitted per second.
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The Correct Option isD
Solution and Explanation
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Question: 4
The threshold frequency for a metal surface is \(\nu_0\). If radiation of frequency \(3\nu_0\) illuminates the surface, the maximum kinetic energy of photoelectrons is \(E_1\). If the frequency is increased to \(6\nu_0\), the maximum kinetic energy becomes \(E_2\). Then \(\left(\dfrac{E_1}{E_2}\right)\) equals
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For quick calculations,
\[
K_{\max}=h(\nu-\nu_0).
\]
Always subtract the threshold frequency first.
