For a loop placed in a magnetic field varying as
\[
B=B_0\sin\omega t,
\]
first calculate the magnetic flux using
\[
\Phi_B=BA.
\]
Then apply Faraday's law
\[
e=-\frac{d\Phi_B}{dt}.
\]
For a sinusoidal current,
\[
I_{\text{rms}}=\frac{I_0}{\sqrt{2}}.
\]
Remember that the peak induced emf is
\[
e_0=B_0A\omega.
\]