Question:medium

A ray of light QP is incident normally on the face BC of a triangular prism ABC of refractive index 1.5 kept in air, as shown in the figure. Trace the path of the ray as it passes through the prism and give relevant explanation. [Assume $\angle B = 60^\circ, \angle C = 30^\circ, \angle A = 90^\circ$ and face BC is the hypotenuse].

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Always remember for glass ($\mu = 1.5$), the critical angle is approximately $41.8^\circ$. Any internal ray striking a glass-air interface at an angle greater than $41.8^\circ$ (such as $45^\circ$ or $60^\circ$) will always undergo total internal reflection.
  • The ray undergoes refraction at face AC and emerges into air bending away from the normal.
  • The ray undergoes Total Internal Reflection (TIR) at face AC because the angle of incidence exceeds the critical angle.
  • The ray reflects back along its original path QP.
  • The ray passes straight out through face AC without any change in direction.
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The Correct Option is B

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