Step 1: Unknowns.
Let $p_0, p_1, p_2, p_3$ be the four probabilities. Given $p_2 = 0.3$ and $p_3 = 2p_1$.
Step 2: Two equations.
Sum: $p_0 + p_1 + 0.3 + 2p_1 = 1$, so $p_0 + 3p_1 = 0.7$. Mean: $p_1 + 0.6 + 6p_1 = 1.3$, so $p_1 = 0.1$.
Step 3: Solve.
$p_0 = 0.7 - 0.3 = 0.4$.
Final Answer:
Option (B).
\[ \boxed{0.4} \]