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A random variable \(X\) has the probability density function \[ f(x)=Kx,\qquad 0<x<2, \] then the ratio between \(K\) and the mean of \(X\) is

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For a pdf, \[ \int f(x)\,dx=1, \qquad E(X)=\int xf(x)\,dx. \]

Updated On: Jul 18, 2026

\(3:2\)
\(2:3\)
\(5:3\)
\(3:8\)

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The Correct Option is D

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