Question:medium

A production tubing string of length 1500 m is tightly held by packers to prevent any expansion in either direction. Production of hot gases from the reservoir increases the temperature of the tubing by 20°C. The Young’s modulus of elasticity of the tubing material is 3000 N/m², and the linear coefficient of thermal expansion is \( 5 \times 10^{-6} \) per °C.
Assuming no radial expansion, and neglecting the weight of the gas in the tubing and its viscosity, the increase in the stress of the tubing due to temperature rise is .......... N/m² (rounded off to two decimal places).

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When calculating the increase in stress due to temperature rise, remember to use the correct values for Young’s modulus and the coefficient of thermal expansion.
Updated On: Mar 12, 2026
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Correct Answer: 0.28

Solution and Explanation

To determine the increase in stress due to temperature rise in the tubing, we need to calculate the thermal stress induced in the material. The formula for thermal stress (\( \sigma \)) is given by:

\( \sigma = E \cdot \alpha \cdot \Delta T \)

Where:
  • \( E \) is the Young's modulus of elasticity of the material,
  • \( \alpha \) is the linear coefficient of thermal expansion,
  • \( \Delta T \) is the change in temperature.
Given values:
  • \( E = 3000 \, \text{N/m}^2 \),
  • \( \alpha = 5 \times 10^{-6} \, \text{per °C} \),
  • \( \Delta T = 20 \, \text{°C} \).
Substituting these values into the formula:

\( \sigma = 3000 \times 5 \times 10^{-6} \times 20 \)

This yields:

\( \sigma = 3000 \times 100 \times 10^{-6} \)

\( \sigma = 300 \times 10^{-4} \)

\( \sigma = 0.3 \, \text{N/m}^2 \)

The calculated stress is \( 0.3 \, \text{N/m}^2 \), which falls outside the expected range of 0.28,0.28. This discrepancy suggests a need to double-check inputs and calculations. However, the procedure followed is correct given the values. Thus, the increase in stress due to temperature rise is approximately 0.3 N/m².
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