Question

A pressure of \( 500 \, \text{kPa} \) applied to \( 2 \, \text{m}^3 \) of liquid results in a volume change of \( 0.004 \, \text{m}^3 \). The bulk modulus in MPa is:

• A. 2.5
• B. 25
• C. 250
• D. 2500

Hint:

Bulk modulus measures a fluid’s resistance to compression; higher values indicate less compressibility.

Answer 1

The Correct Option is B

The bulk modulus (\( K \)) is determined using the following formula:

\( K = \frac{\Delta P}{\Delta V / V} \)

Upon substituting \( \Delta P = 500 \, \text{kPa}, \, V = 2 \, \text{m}^3, \) and \( \Delta V = 0.004 \, \text{m}^3 \), the result is:

\( K = \frac{500}{0.004 / 2} = 25 \, \text{MPa}. \)