Question:medium

A potentiometer wire of length \(10\) m and resistance \(9\,\Omega\) is connected to a cell of emf \(E\) and internal resistance \(1\,\Omega\). If \(V\) is the maximum potential difference that can be measured using the potentiometer, then the condition for the potentiometer to work is

Show Hint

For a potentiometer, \[ \boxed{ V_{\max}=IR_{\text{wire}}. } \] The unknown potential difference must always satisfy \[ \boxed{ V\le V_{\max}. } \]
Updated On: Jul 18, 2026
  • \(E=V\)
  • \(9E\ge10V\)
  • \(E<V\)
  • \(9V=10E\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0