Question:medium

A point source is kept at centre of a sphere. The intensity of light at point \(A\) is \(I\). Find intensity at point \(B\).

Updated On: Apr 8, 2026
  • \(I/2\)
  • \(2I\)
  • \(I\)
  • \(I/3\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
For a uniform point source of light, the intensity radiates equally in all directions (isotropically). It only depends on the radial distance from the source following the inverse-square law.
Step 2: Key Formula or Approach:
The intensity \(I\) at a distance \(R\) from a source of power \(P\) is: \[ I = \frac{P}{4\pi R^2} \]
Step 3: Detailed Explanation:
The light source is located perfectly at the center of the sphere. Both points A and B lie on the surface of the sphere. Because they are on the surface, the radial distance from the center to point A is \(R\), and the radial distance to point B is also \(R\). Since the intensity strictly depends on the distance \(R\) and not the angular position: \[ I_A = \frac{P}{4\pi R^2} = I \] \[ I_B = \frac{P}{4\pi R^2} = I \] Therefore, the intensity at B is exactly the same as at A.
Step 4: Final Answer:
The intensity at point B is \(I\).
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