Question:medium
A point P on an ellipse is at a distance 6 units from a focus. If the eccentricity of the ellipse is \( \frac{3}{5} \), then the distance of P from the corresponding directrix is:
A point P on an ellipse is at a distance 6 units from a focus. If the eccentricity of the ellipse is \( \frac{3}{5} \), then the distance of P from the corresponding directrix is:
Show Hint
The focus-directrix property applies to all conics. Just remember the mnemonic: "Focus distance is $e$ times Directrix distance" ($PS = e \cdot PM$).
Updated On: May 6, 2026
- \( \frac{8}{5} \)
- \( \frac{5}{8} \)
- \( 10 \)
- \( 12 \)
- \( 15 \)
Show Solution
The Correct Option is C
Solution and Explanation
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