A point on a taut string is moving up and down due to a wave travelling along it. The point completes 120 cycles in one fourth of a minute. The frequency of the wave is:

Question

A transverse wave along a string is given by \( y = 2 \sin \left( 2\pi (3t - x) + \frac{\pi{4} \right) \), where \( x \) and \( y \) are in cm and \( t \) in second. Find the acceleration of a particle located at \( x = 4 \) cm at \( t = 1 \) s.}

Answer 1

Step 1: Time interval conversion.
One fourth of a minute equals 15 seconds.

Step 2: Frequency calculation.
f = number of cycles / time = 120 / 15 = 8 Hz.

Step 3: Conclusion.
The wave frequency is 8 Hz.

A point on a taut string is moving up and down due to a wave travelling along it. The point completes 120 cycles in one fourth of a minute. The frequency of the wave is:

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The Correct Option is A

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