Question:medium
A plane passes through the point \( (1,-2,1) \) and is perpendicular to planes \(2x-2y+z=0\) and \(x-y+2z=4\). Then the equation of the plane is
A plane passes through the point \( (1,-2,1) \) and is perpendicular to planes \(2x-2y+z=0\) and \(x-y+2z=4\). Then the equation of the plane is
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Plane perpendicular to two planes ⇒ normal is cross product.
Updated On: Apr 30, 2026
- \(x+y+1=0\)
- \(x-y+1=0\)
- \(x+2y+1=0\)
- \(x-2y+1=0\)
- \(x-y-1=0\)
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The Correct Option is D
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