Question

A pipe with diameter 25 cm at the entrance carries oil with specific gravity 0.9 at a velocity of 3 m/s. At the exit section the diameter of the pipe is 20 cm. The velocity at the exit section is:

• A. 4.5 m/s
• B. 4.68 m/s
• C. 4.8 m/s
• D. 4.9 m/s

Hint:

For incompressible flow, use the continuity equation to relate the velocity and cross-sectional areas at different points.

Answer 1

The Correct Option is B

Step 1: Apply the continuity equation.
The continuity equation for incompressible flow is stated as:\[A_1 v_1 = A_2 v_2\]Where:- \( A_1 = \frac{\pi d_1^2}{4} \) represents the cross-sectional area at the inlet,- \( A_2 = \frac{\pi d_2^2}{4} \) represents the cross-sectional area at the outlet,- \( v_1 = 3 \, \text{m/s} \) is the velocity at the inlet,- \( d_1 = 0.25 \, \text{m} \) and \( d_2 = 0.20 \, \text{m} \) are the diameters at the inlet and outlet, respectively.

Step 2: Determine \( v_2 \).
Rearranging the continuity equation to solve for \( v_2 \):\[v_2 = v_1 \times \frac{A_1}{A_2} = 3 \times \frac{\left( \frac{\pi (0.25)^2}{4} \right)}{\left( \frac{\pi (0.20)^2}{4} \right)} = 3 \times \left(\frac{0.25^2}{0.20^2}\right) = 3 \times \left(\frac{0.0625}{0.04}\right) = 4.68 \, \text{m/s}\]

Final Answer: \[\boxed{4.68 \, \text{m/s}}\]