Question:medium
A person with his hand in his pocket is skating on ice at the rate of \(10 \text{ m s}^{-1}\) and describes a circle of radius \(50 \text{ m}\). What is his inclination to vertical? \((g = 10 \text{ m s}^{-2})\)
A person with his hand in his pocket is skating on ice at the rate of \(10 \text{ m s}^{-1}\) and describes a circle of radius \(50 \text{ m}\). What is his inclination to vertical? \((g = 10 \text{ m s}^{-2})\)
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For circular motion on ice, inclination depends on centripetal acceleration \(v^2/r\).
Updated On: Mar 24, 2026
- \(\tan^{-1}\left(\frac{1}{2}\right)\)
- \(\tan^{-1}\left(\frac{1}{5}\right)\)
- \(\tan^{-1}\left(\frac{3}{5}\right)\)
- \(\tan^{-1}\left(\frac{1}{10}\right)\)
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The Correct Option is A
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