A person standing between two parallel cliffs fires a gun and hears two echoes, first echo after $1$ second and the second echo after $3$ second. The distance between the two cliffs is (Velocity of sound $= 340\text{ m/s}$ )
Show Hint
Echo formula:
\[
d=\frac{vt}{2}
\]
because sound travels to the cliff and comes back.
Step 1: Understanding the Concept:
Sound travels from the person to a cliff and reflects back. The time taken for an echo is for the distance to the cliff and back. Step 2: Key Formula or Approach:
Distance $d = \frac{v \times t}{2}$. Step 3: Detailed Explanation:
Distance to first cliff $d_1 = \frac{340 \times 1}{2} = 170\text{ m}$.
Distance to second cliff $d_2 = \frac{340 \times 3}{2} = 510\text{ m}$.
Total distance between cliffs $= d_1 + d_2 = 170 + 510 = 680\text{ m}$. Step 4: Final Answer:
The distance is $680\text{ m}$.